If ∫ f(x) dx = φ(x), then
b ∫ a f(x) dx = [φ(x)] b a = φ(b) − φ(a)
b ∫ a f(x) dx = [φ(x)] b a = φ(b) − φ(a)
| 1. | b ∫ a [f(x) ± g(x)] dx = b ∫ a f(x) dx ± b ∫ a g(x) dx | ||||
| 2. | b ∫ a k f(x) dx = k b ∫ a f(x) dx , where k is constant | ||||
| 3. | b ∫ a [k1f(x) ± k2g(x)] dx = k1 b ∫ a f(x) dx ± k2 b ∫ a g(x) dx | ||||
| 4. | b ∫ a f(x) dx = b ∫ a f(t) dt | ||||
| 5. | b ∫ a f(x) dx = − a ∫ b f(x) dx | ||||
| 6. | If a < c < b, then b ∫ a f(x) dx = c ∫ a f(x) dx + b ∫ c f(x) dx | ||||
| 7. | a ∫ 0 f(x) dx = a ∫ 0 f(a − x) dx | ||||
| 8. | b ∫ a f(x) dx = b ∫ a f(a + b − x) dx | ||||
| 9. |
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| 10. | 2a ∫ 0 f(x) dx = a ∫ 0 [f(x) + f(2a − x)] dx |