The process of finding the function of a given derivative.
The integral gives the area under the curve of a function.
If φ´(x) = f(x), then
φ(x) + c is an indefinite integral of f(x) and is denoted as ∫ f(x) dx = φ(x) + c.
φ(x) + c is an indefinite integral of f(x) and is denoted as ∫ f(x) dx = φ(x) + c.
| ∫ dx | = x + c |
| ∫ k dx | = kx + c , where k is constant |
| ∫ k f(x) dx | = k ∫ f(x) dx , where k is constant |
| ∫ x dx | = x2 2 + c |
| ∫ xn dx | = xn + 1 n + 1 + c , where n ≠ -1 |
| ∫ (ax + b) dx | = 1 a (ax + b) + c |
| ∫ (ax + b)n dx | = (ax + b)n + 1 a (n + 1) + c , where n ≠ -1 |
| ∫ 1 x dx | = ln x + c |
| ∫ 1 ax + b dx | = 1 a ln ax + b + c |
| ∫ ex dx | = ex + c |
| ∫ ax dx | = ax ln(a) + c |
| = ax logae + c | |
| ∫ ln(x) dx | = x ln(x) − x + c |
| ∫ x dx | = x3/2 3/2 |
| ∫ 1 a2 − x2 dx | = sin-1 x a + c |
| = − cos-1 x a + c | |
| ∫ 1 x2 + a2 dx | = ln x + x2 + a2 + c |
| ∫ 1 x2 − a2 dx | = ln x + x2 − a2 + c |
| ∫ 1 a2 + x2 dx | = 1 a tan-1x a + c |
| = − 1 a cot-1x a + c | |
| ∫ 1 a2 − x2 dx | = 1 2a log a + x a − x + c |
| ∫ 1 x2 − a2 dx | = 1 2a log x − a x + a + c |
| ∫ sin(x) dx | = − cos(x) + c |
| ∫ cos(x) dx | = sin(x) + c |
| ∫ tan(x) dx | = − ln cos(x) + c |
| ∫ cot(x) dx | = ln sin(x) + c |
| ∫ sec(x) dx | = ln sec(x) + tan(x) + c |
| ∫ cosec(x) dx | = − ln cosec(x) + cot(x) + c |
| ∫ sec2(x) dx | = tan(x) + c |
| ∫ sin-1(x) dx | = x sin-1(x) + 1 - x2 + c |
| ∫ cos-1(x) dx | = x cos-1(x) + 1 - x2 + c |
| ∫ tan-1(x) dx | = x tan-1(x) − ln(1 + x2) 2 + c |
| ∫ cot-1(x) dx | = x cot-1(x) + ln(1 + x2) 2 + c |
| ∫ sec-1(x) dx | = x sec-1(x) − ln x + x x2 − 1 x2 + c |
| ∫ cosec-1(x) dx | = x cosec-1(x) + ln x + x x2 − 1 x2 + c |
| ∫ sinh(x) | = cosh(x) + c |
| ∫ cosh(x) | = sinh(x) + c |
| ∫ tanh(x) | = ln cosh(x) + c |
| ∫ coth(x) | = ln sinh(x) + c |
| ∫ sech(x) | = tan-1sinh(x) + c |
| ∫ cosech(x) | = ln tanh(x/2) + c |
∫(u + v)dx = ∫ u dx + ∫ v dx
∫(u − v)dx = ∫ u dx − ∫ v dx
∫ku dx = k ∫ u dx , where k is a constant
∫(uv) dx = u ∫ v dx − ∫ [
du dx
∫ v dx ] dx| 1. | If x = φ(t) is a differential function of t, then: ∫ f(x) dx = ∫ f[φ(t)] φ´(t) dt |
| 2. | If ∫ f(x) dx = φ(x), then: ∫ f(ax + b) dx = φ(ax + b) a + c |
| 3. | ∫ [f(x)]n f´(x) dx = [f(x)]n + 1 n + 1 + c |
| 4. | ∫ f´(x) f(x) dx = logf(x) + c |
| 5. | ∫ f´(x) n f(x) dx = [f(x)]1 - (1/n) 1 − (1/n) + c |